If you are planning to go on vacation with your family then enter the Washington DC Tourism Family Fun Summer Sweepstakes now through June 30, 2018 for your chance to win the ultimate getaway for four to Washington, DC. Trip Includes: Hotel accommodations, tours of the city and waterfront adventures, $100 gift certificate and more.
Prizes You Could Win: The Normandy Hotel: Two-night stay for four, American Airlines: Four roundtrip tickets, DC Circulator: Eight one-way passes, District Doughnut: A dozen doughnuts, Hen Quarter: $100 gift certificate, Big Bus: Hop-on, Hop-off tour of Washington, DC, Capital SUP DC: One-hour paddle board or kayak rental for four, Escape Room Live: 1 Escape Room Activity. Total ARV of prize is over $1,800.
Washington DC Tourism Family Fun Summer Sweepstakes Rules
- Who Can Enter: This sweepstakes is open only to legal residents of the United States who are twenty one (21) years of age or older at the time they enter the sweepstakes.
- When To Enter: The Washington DC Tourism Family Fun Summer Sweepstakes entry begins on June 4, 2018 and 11:59 PM Eastern Standard Time (EST) on June 30, 2018.
- Winner Selection: One qualified Entrant will be selected and gifted Prize A by random drawing held on July 10, 2018. Odds of winning depend on total number of qualified entries received.
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